Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
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2014-11-21 06:56:07
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122
Divide two integers without using multiplication, division and mod operator.代码：class Solution {private: int res;public: int solve(long long divi...
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其他好文 时间：
2014-11-20 11:45:17
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Given two numbers represented as strings, return multiplication of the numbers as a string.
Note: The numbers can be arbitrarily large and are non-negative.
原题链接：https://oj.leetcode.com/problems...
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其他好文 时间：
2014-11-19 01:52:17
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A Multiplication GameTime Limit: 5000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 3832Accepted Submission(s): 2...
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2014-11-17 19:12:46
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129
Brightness and contrast adjustments Two commonly used point processes are multiplication and addition with a constant: The parameters and are often ca...
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其他好文 时间：
2014-11-16 21:24:27
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263
Multiplication Puzzle
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 6542
Accepted: 3983
Description
The multiplication puzzle is played with a row of car...
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其他好文 时间：
2014-11-16 17:26:48
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188
Let $X$ be nay basis of $\scrH$ and let $Y$ be the basis biorthogonal to it. Using matrix multiplication, $X$ gives a linear transformation from $\bbC...
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2014-11-16 11:53:20
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Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
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其他好文 时间：
2014-11-13 23:47:53
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177
Divide two integers without using multiplication, division and mod operator.
显然，如果光用减法太慢。让商为N，那么需要用O(N)的时间。这里要求比较苛刻，连乘法都不能使用，所以只能寄希望于二进制操作了。
这里可以把除数表示为：dividend = 2^i * divisor + 2^(i-1) * divisor +...
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其他好文 时间：
2014-11-11 02:02:27
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214
