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Divide Two Integers
Divide two integers without using multiplication, division and mod operator.分析:不能用乘、除、取模运算,我们可以用的运算还有加、减、位运算。一个比较简单的想法是在dividend上不断减去divisor,知道余数小于div...
分类:其他好文   时间:2014-10-20 21:18:28    阅读次数:183
LeetCode-Divdend two Integers
题目:Divide two integers without using multiplication, division and mod operator.思路分析二分法.将除数不断增倍,而结果同样扩大两倍,直到除数的值大于被除数.然后再利用被除数减去除数最后增长到小于被除数的值,递归求出结果.例...
分类:其他好文   时间:2014-10-19 01:19:32    阅读次数:288
POJ3213(矩阵乘法)
PM3 Time Limit: 5000MS   Memory Limit: 131072K Total Submissions: 3036   Accepted: 1059 Description USTC has recently developed the Parallel Matrix Multiplication Machi...
分类:其他好文   时间:2014-10-11 20:09:16    阅读次数:223
Multiply Strings
[leetcode]Given two numbers represented as strings, return multiplication of the numbers as a string....
分类:其他好文   时间:2014-10-09 16:02:38    阅读次数:174
[2-SAT] poj 3678 Katu Puzzle
题目链接: http://poj.org/problem?id=3678 Katu Puzzle Time Limit: 1000MS   Memory Limit: 65536K Total Submissions: 7888   Accepted: 2888 Description Katu Puzzl...
分类:其他好文   时间:2014-10-09 02:52:28    阅读次数:227
Multiply Strings
Given two numbers represented as strings, return multiplication of the numbers as a string.Note: The numbers can be arbitrarily large and are non-nega...
分类:其他好文   时间:2014-10-05 20:05:58    阅读次数:208
Divide Two Integers
Divide two integers without using multiplication, division and mod operator.方法一:暴力破解,不断用被除数减去除数,直至出现负数停止,铁定超时。方法二:对方法一的改进,每次寻找 满足2k-1 * 除数 0 && diviso...
分类:其他好文   时间:2014-10-02 01:55:51    阅读次数:271
[LeetCode] Multiply Strings 字符串相乘
Given two numbers represented as strings, return multiplication of the numbers as a string. Note: The numbers can be arbitrarily large and are non-negative. 这个题说数可能是任意的大的非负数,肯定不是让你直接乘起来返回(我干了。。)而是...
分类:其他好文   时间:2014-09-30 06:45:32    阅读次数:167
A Multiplication Game
A Multiplication Gamehttp://acm.hdu.edu.cn/showproblem.php?pid=1517Time Limit: 5000/1000 MS (Java/Others)Memory Limit: 65536/32768 K (Java/Others)Tota...
分类:其他好文   时间:2014-09-27 00:44:48    阅读次数:194
UVa 348 - Optimal Array Multiplication Sequence
题目:矩阵连乘,求最小运算次数,输出运算优先级(用括号给出)。 分析:dp,区间动态规划。             状态:设DP[ l ][ s ]为以 s 开始长度为 l 的区间的 矩阵乘积的最小值;             阶段:区间长度;             决策:DP[ l ][ s ] = min(DP[ k ][ s ] + DP[ l-k ][ s+k ] + 乘法代价)...
分类:其他好文   时间:2014-09-21 23:54:01    阅读次数:272
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