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【我的学习笔记】汇总
Life is filled with endless meaningful things to learn, if it is gonna be a fulfilling life.
分类:其他好文   时间:2015-07-12 21:37:55    阅读次数:140
[leedcode 55] Jump Game
Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your maximu...
分类:其他好文   时间:2015-07-12 17:04:29    阅读次数:165
leetCode 45.Jump Game II (跳跃游戏) 解题思路和方法
Jump Game II Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length at that position...
分类:其他好文   时间:2015-07-12 14:21:04    阅读次数:125
[leedcode 45] Jump Game II
Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your maximu...
分类:其他好文   时间:2015-07-11 10:34:31    阅读次数:114
【To Read】LeetCode | Jump Game II(转载)
题目:Given an array of non-negative integers, you are initially positioned at the first index of the array.Each element in the array represents your max...
分类:其他好文   时间:2015-07-02 15:24:11    阅读次数:94
LInux Shell 快捷键
CTRL 键相关的快捷键:Ctrl + a - Jump to the start of the lineCtrl + b - Move back a charCtrl + c - Terminate the command //用的最多了吧?Ctrl + d - Delete from under...
分类:系统相关   时间:2015-07-01 14:02:57    阅读次数:130
Jump gameII
leetcode jump gameII 看了题解,用BFS是比较好的思路,一层表示当前步能到的节点,curmax表示最远的,和贪心有异曲同工之妙 class Solution { public: int jump(vector& a) { int n=a.size(); if(n<=1) return 0; int i=0, level...
分类:其他好文   时间:2015-07-01 10:06:40    阅读次数:112
[leetcode]Jump Game
转载请注明出处:http://www.cnblogs.com/StartoverX/p/4611518.html题目:Given an array of non-negative integers, you are initially positioned at the first index of...
分类:其他好文   时间:2015-06-30 21:51:24    阅读次数:107
leetcode - Jump Game II
题目: Jump Game II   Given an array of non-negative integers, you are initially positioned at the first index of the array. Each element in the array represents your maximum jump length ...
分类:其他好文   时间:2015-06-29 10:06:13    阅读次数:103
unity5, UGUI刺穿问题解法
我希望在touch屏幕时player起跳,于是在playerControl.cs的Update函数中添加如下touch代码: if(Input.GetMouseButtonDown(0)){//leftbuttondown jump(); }同时我在屏幕左上角加了一个实现暂停的pau...
分类:编程语言   时间:2015-06-29 06:19:50    阅读次数:2112
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