亲戚Time Limit:1000MSMemory
Limit:65535KBSubmissions:214Accepted:82Description若某个家族人员过于庞大,要判断两个是否是亲戚,确实还很不容易,现在给出某个亲戚关系图,求任意给出的两个人是否具有亲戚关系。
规定:x和y是亲戚,y和...
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其他好文 时间:
2014-05-08 11:21:14
阅读次数:
307
汉字统计Time Limit: 2000/1000 MS
(Java/Others)Memory Limit: 65536/32768 K (Java/Others)Total Submission(s):
22508Accepted Submission(s): 12255Problem Desc...
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其他好文 时间:
2014-05-08 10:04:00
阅读次数:
306
K-th NumberTime Limit:20000MSMemory
Limit:65536KTotal Submissions:35653Accepted:11382Case Time
Limit:2000MSDescriptionYou are working for Macrohard co...
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其他好文 时间:
2014-05-08 05:24:50
阅读次数:
387
题目链接:
http://acm.hdu.edu.cn/showproblem.php?pid=2841
Visible Trees
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 1337 Accepted S...
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其他好文 时间:
2014-05-08 04:45:47
阅读次数:
375
Help Me Escape
Time Limit: 2 Seconds Memory Limit: 32768 KB
Background
If thou doest well, shalt thou not be accepted? and if thou doest not well, sin lieth at the door. And unto the...
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其他好文 时间:
2014-05-08 01:37:02
阅读次数:
353
点击打开链接
ROADS
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 10202
Accepted: 3786
Description
N cities named with numbers 1 ... N are connected with o...
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其他好文 时间:
2014-05-07 23:42:01
阅读次数:
617
Hotter Colder
Time Limit: 1000MS
Memory Limit: 65536K
Total Submissions: 2343
Accepted: 981
Description
The children's game Hotter Colder is played as follows. Player A...
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其他好文 时间:
2014-05-07 23:39:58
阅读次数:
590
确定比赛名次
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 10358 Accepted Submission(s): 4046
Problem Description
有N个比赛队(1
...
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其他好文 时间:
2014-05-07 22:58:01
阅读次数:
323
N的范围很大,但Q的范围比较小.可以把TOP,QUERY操作用到的点分离出来,没用到的段缩成点
对于TOP 把x转到根,删除后加到开头位置
对于QUERY 旋转到根直接输出
对于RANK,递归
Queue-jumpers
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Othe...
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其他好文 时间:
2014-05-07 22:36:28
阅读次数:
559
defgetResult(cmd,timeout=2):#命令超时时间
deadline=time.time()+timeout
r=subprocess.Popen(cmd,shell=True,stdout=subprocess.PIPE)
whiletime.time()<deadlineandr.poll()isNone:
time.sleep(0.1)
ifr.poll()isNone:#检查子进程
r.kill()
r.wait()
return‘‘
r.wait()
..
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编程语言 时间:
2014-05-07 22:30:17
阅读次数:
504