Blue Jeans

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Description

Input

Output

Sample Input

3
2
GATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATA
AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
3
GATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATACCAGATA
GATACTAGATACTAGATACTAGATACTAAAGGAAAGGGAAAAGGGGAAAAAGGGGGAAAA
GATACCAGATACCAGATACCAGATACCAAAGGAAAGGGAAAAGGGGAAAAAGGGGGAAAA
3
CATCATCATCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCCC
ACATCATCATAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA
AACATCATCATTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTTT

Sample Output

no significant commonalities
AGATAC
CATCATCAT

题解：求最长的公共字串并且按照字典序找最小的一个，由于长度小，暴力。

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>

using namespace std;

string s[20];

int main()
{
	int ncase;
	cin>>ncase;
	while(ncase--)
	{
		int n;
		scanf("%d",&n);
		for(int i = 0;i < n;i++)
		{
			cin>>s[i];
		}
		bool flag = false;
		string res = "Z";
		for(int i = 60;i > 2;i--)
		{
			for(int j = 0;j <= 60 - i;j++)
			{
				string s1(s[0],j,i);
				bool f = true;
				for(int k = 1;k < n;k++)
				{
					if(s[k].find(s1) == string::npos)
					{
						f = false;
						break;
					}
				}
				if(f)
				{
					if(res > s1)
					{
						res = s1;
					}
					flag = true;
				}
			}
			if(flag)
			{
				break;
			}
		}
		
		if(flag)
		{
			cout<<res<<endl;
		}
		else
		{
			cout<<"no significant commonalities\n";
		}
	}
	
	
	
	return 0;
}

Blue Jeans

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原文地址：http://blog.csdn.net/wang2534499/article/details/47973931