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[LeetCode 191] Number of 1 Bits

时间:2015-09-02 18:58:52      阅读:133      评论:0      收藏:0      [点我收藏+]

标签:leetcode   bit   

Write a function that takes an unsigned integer and returns the number of ’1‘ bits it has (also known as the Hamming weight).

For example, the 32-bit integer ’11‘ has binary representation 00000000000000000000000000001011, so the function should return 3.

solution:

1. every time n&1, until n==0. 

2. n&(n-1) will remove last 1 digit in n, use this to count how many 1 in the number


public int hammingWeight(int n) {
        int count = 0;
        while(n!=0){
            n = (n-1) & n;
            count++;
        }
        return count;
    }




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[LeetCode 191] Number of 1 Bits

标签:leetcode   bit   

原文地址:http://blog.csdn.net/sbitswc/article/details/48176391

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