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9
/ \
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5 8
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/ \ \
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1 4 7
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/ \ /
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2 3 6
就是从最左边开始, 遍历五次,
1,
2,
3, 4, 5
6,
7, 8, 9,
最后结果是 1 2 3 4 5 6 7 8 9
加一个dummy node, with left child is the root node.
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Morris post order traversal algorithm
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原文地址：http://www.cnblogs.com/juliachenOnSoftware/p/4806102.html
