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Time Limit: 12000/4000 MS (Java/Others) Memory Limit: 104857/104857 K (Java/Others)
Total Submission(s): 3568 Accepted Submission(s): 1235
#include<stdio.h>
#include<string.h>
#include<algorithm>
#include<stack>
#include<vector>
#define MAX 50010
#define INF 0x3f3f3f
using namespace std;
int n,m;
int ans,head[MAX];
int low[MAX],dfn[MAX];
int instack[MAX],sccno[MAX];
vector<int>newmap[MAX];
vector<int>scc[MAX];
int scccnt,dfsclock;
int in[MAX],out[MAX];
stack<int>s;
struct node
{
int beg,end,next;
}edge[MAX];
void init()
{
ans=0;
memset(head,-1,sizeof(head));
}
void add(int beg,int end)
{
edge[ans].beg=beg;
edge[ans].end=end;
edge[ans].next=head[beg];
head[beg]=ans++;
}
void getmap()
{
int i,a,b;
while(m--)
{
scanf("%d%d",&a,&b);
add(a,b);
}
}
void tarjan(int u)
{
int v,i,j;
s.push(u);
instack[u]=1;
low[u]=dfn[u]=++dfsclock;
for(i=head[u];i!=-1;i=edge[i].next)
{
v=edge[i].end;
if(!dfn[v])
{
tarjan(v);
low[u]=min(low[u],low[v]);
}
else if(instack[v])
low[u]=min(low[u],dfn[v]);
}
if(low[u]==dfn[u])
{
scccnt++;
while(1)
{
v=s.top();
s.pop();
instack[v]=0;
sccno[v]=scccnt;
if(v==u)
break;
}
}
}
void find(int l,int r)
{
memset(low,0,sizeof(low));
memset(dfn,0,sizeof(dfn));
memset(instack,0,sizeof(instack));
memset(sccno,0,sizeof(sccno));
dfsclock=scccnt=0;
for(int i=l;i<=r;i++)
{
if(!dfn[i])
tarjan(i);
}
}
void suodian()
{
int i;
for(i=1;i<=scccnt;i++)
{
newmap[i].clear();
in[i]=0;out[i]=0;
}
for(i=0;i<ans;i++)
{
int u=sccno[edge[i].beg];
int v=sccno[edge[i].end];
if(u!=v)
{
newmap[u].push_back(v);
in[v]++;out[u]++;
}
}
}
void solve()
{
int i,j;
if(scccnt==1)
{
printf("0\n");
return ;
}
else
{
int minn=0;
int maxx=0;
for(i=1;i<=scccnt;i++)
{
if(!in[i])
minn++;
if(!out[i])
maxx++;
}
printf("%d\n",max(minn,maxx));
}
}
int main()
{
while(scanf("%d%d",&n,&m)!=EOF)
{
init();
getmap();
find(1,n);
suodian();
solve();
}
return 0;
}
hdoj 3836 Equivalent Sets【scc&&缩点】【求最少加多少条边使图强连通】
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原文地址:http://www.cnblogs.com/tonghao/p/4820724.html