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LeetCode -- Maximum Depth of Binary Tree

时间:2015-09-20 14:29:30      阅读:111      评论:0      收藏:0      [点我收藏+]

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Question:

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

 

Analysis:

问题描述:给出一棵二叉树,求出它的最大深度。最大深度是指从根节点到最远的叶子节点的深度。

思路一:递归求解。分别求左子树的深度和右子树的深度,然后返回较深的一边的深度。

 

Answer:

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode(int x) { val = x; }
 * }
 */
public class Solution {
 public int maxDepth(TreeNode root) {
        if(root == null)
            return 0;
        int left = maxDepth(root.left);
        int right = maxDepth(root.right);
        
        return left > right ? left + 1 : right + 1;
    }
    
}

 

LeetCode -- Maximum Depth of Binary Tree

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原文地址:http://www.cnblogs.com/little-YTMM/p/4823363.html

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