标签:
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 37350 Accepted Submission(s):
16905

#include<stdio.h>
#include<string.h>
double b[20];
double fun(int x)
{
int i;
double sum=1.0,a=1.0;
for(i=1;i<=x;i++)
{
sum=a*sum;
a=a+1;
}
sum=1/sum;
return sum;
}
int main()
{
int n,m,j,i;
double sum=0;
b[0]=1;b[1]=1;
for(i=2;i<=9;i++)
b[i]=fun(i);
printf("n e\n");
printf("- -----------\n");
for(i=0;i<=9;i++)
{
printf("%d ",i);
sum+=b[i];
if(i==2)
{
printf("2.5\n");
continue;
}
if(sum==(int)(sum))
printf("%d\n",(int)(sum));
else
printf("%.9lf\n",sum);
}
return 0;
}
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原文地址:http://www.cnblogs.com/tonghao/p/4910996.html