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挺简单的，多占内存，少用循环
Behind the scenes in the computer‘s memory, color is always talked about as a series of 24 bits of information for each pixel. In an image, the color with the largest proportional area is called the dominant color. A strictly dominant color takes more than half of the total area. Now given an image of resolution M by N (for example, 800x600), you are supposed to point out the strictly dominant color.
Input Specification:
Each input file contains one test case. For each case, the first line contains 2 positive numbers: M (<=800) and N (<=600) which are the resolutions of the image. Then N lines follow, each contains M digital colors in the range [0, 224). It is guaranteed that the strictly dominant color exists for each input image. All the numbers in a line are separated by a space.
Output Specification:
For each test case, simply print the dominant color in a line.
Sample Input:5 3 0 0 255 16777215 24 24 24 0 0 24 24 0 24 24 24Sample Output:
24
#pragma warning(disable:4996)#include <stdio.h>using namespace std;int a[16777216];int main(void) {int m, n;scanf("%d %d", &m, &n);int p = m*n,temp,count=0,result=0;for (int i = 0; i < p; i++) {scanf("%d", &temp);a[temp]++;if (a[temp] > count) {count = a[temp];result = temp;}}printf("%d", result);return 0;}
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原文地址：http://www.cnblogs.com/zzandliz/p/5023178.html
