标签:
1 5
1 0Consider the second test case: The initial condition : 0 0 0 0 0 … After the first operation : 1 1 1 1 1 … After the second operation : 1 0 1 0 1 … After the third operation : 1 0 0 0 1 … After the fourth operation : 1 0 0 1 1 … After the fifth operation : 1 0 0 1 0 … The later operations cannot change the condition of the fifth lamp any more. So the answer is 0.Hinthint
#include <iostream>
using namespace std;
int main()
{
int n;
while (cin >> n)
{
int num=0;
for (int i=1; i<=n; i++)
{
if (n %i ==0)
num++;
}
if (num%2 == 0)
cout << 0;
else
cout << 1;
cout <<endl;
}
return 0;
}标签:
原文地址:http://www.cnblogs.com/mengfanrong/p/5030742.html