【转】连接MySQL数据库(android,php,MySQL)

1 CREATE TABLE `people` (
2 `id` INT NOT NULL AUTO_INCREMENT PRIMARY KEY ,
3 `name` VARCHAR( 100 ) NOT NULL ,
4 `sex` BOOL NOT NULL DEFAULT ‘1‘,
5 `birthyear` INT NOT NULL
6 )

 1 <?php
 2 /* 连接到数据库 */
 3 mysql_connect("host","username","password");
 4 mysql_select_db("PeopleData");
 5 /* $_REQUEST[‘year‘]获得Android发送的年值,拼接一个SQL查询语句 */
 6 $q=mysql_query("SELECT * FROM people WHERE birthyear>‘".$_REQUEST[‘year‘]."‘"); 
 7 while($e=mysql_fetch_assoc($q))
 8         $output[]=$e;
 9 /* 转换以JSON格式输出　 */
10 print(json_encode($output));
11 
12 mysql_close();
13 ?>

 1 String result = "";
 2 /* 设定发送的年值 */
 3 ArrayList<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>();
 4 nameValuePairs.add(new BasicNameValuePair("year","1980"));
 5 
 6 /* 用HttpPost发送年值 */
 7 try{
 8         HttpClient httpclient = new DefaultHttpClient();
 9         HttpPost httppost = new HttpPost("http://example.com/getAllPeopleBornAfter.php");//上面php所在URL
10         httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
11         HttpResponse response = httpclient.execute(httppost);
12         HttpEntity entity = response.getEntity();
13         InputStream is = entity.getContent();
14 }catch(Exception e){
15         Log.e("log_tag", "联网错误 "+e.toString());
16 }
17 /* 转换响应字符串 */
18 try{
19         BufferedReader reader = new BufferedReader(new InputStreamReader(is,"iso-8859-1"),8);//注意"iso-8859-1"编码不支持中文。
20         /* 如需支持中文，设定MySQL为UTF8格式，在此也设置UTF8读取 */
21         StringBuilder sb = new StringBuilder();
22         String line = null;
23         while ((line = reader.readLine()) != null) {
24                 sb.append(line + "\n");
25         }
26         is.close();
27 
28         result=sb.toString();
29 }catch(Exception e){
30         Log.e("log_tag", "转换响应字符串错误 "+e.toString());
31 }
32 
33 /* 解析JSON数据 */
34 try{
35         JSONArray jArray = new JSONArray(result);
36         for(int i=0;i<jArray.length();i++){
37                 JSONObject json_data = jArray.getJSONObject(i);
38                 Log.i("log_tag","id: "+json_data.getInt("id")+
39                         ", name: "+json_data.getString("name")+
40                         ", sex: "+json_data.getInt("sex")+
41                         ", birthyear: "+json_data.getInt("birthyear")
42                 );
43         }
44 }
45 }catch(JSONException e){
46         Log.e("log_tag", "解析JSON数据错误 "+e.toString());
47 }