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Given a string s consists of upper/lower-case alphabets and empty space characters ‘ ‘, return the length of last word in the string.
If the last word does not exist, return 0.
Given s = "Hello World", return 5.
A word is defined as a character sequence consists of non-space characters only.
public class Solution { /** * @param s A string * @return the length of last word */ public int lengthOfLastWord(String s) { // Write your code here if(s == null) return 0; String str = s.trim(); if(str.length() == 0) return 0; int count = 0; int index = str.length() - 1; while(index >= 0 && str.charAt(index) != ‘ ‘){ count++; index--; } return count; } }
lintcode-easy-Length of Last Word
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原文地址：http://www.cnblogs.com/goblinengineer/p/5218923.html
