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LintCode: Maximum Depth of Binary Tree

时间:2016-03-13 14:29:24      阅读:167      评论:0      收藏:0      [点我收藏+]

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Maximum Depth of Binary Tree:

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

Code:

/**
 * Definition of TreeNode:
 * public class TreeNode {
 *     public int val;
 *     public TreeNode left, right;
 *     public TreeNode(int val) {
 *         this.val = val;
 *         this.left = this.right = null;
 *     }
 * }
 */
public class Solution {
    /**
     * @param root: The root of binary tree.
     * @return: An integer.
     */
    private int depth = 0;
    public int maxDepth(TreeNode root) {
        // write your code here
        // handle corner case
        if (root == null) {
            return 0;
        }
        // start from the root
        helper(root, 1);
        return depth;
    }
    
    private void helper(TreeNode node, int curtDepth) {
        // if reach the null
        if (node == null) {
            return;
        }
        //refresh depth
        if (curtDepth > depth) {
            depth = curtDepth;
        }
        // go for left and right
        helper(node.left, curtDepth + 1);
        helper(node.right, curtDepth + 1);
    }
}

Thr trick here is to set the depth variable and refresh it in the helper method, helper method is a recursive method, the return condition is when we reach the null node.

LintCode: Maximum Depth of Binary Tree

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原文地址:http://www.cnblogs.com/dingjunnan/p/5271775.html

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