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#coding:utf-8
‘‘‘
折半查找返回值是mid+1
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def half_search(data,target):
    low,high = 0,len(data)-1
    while low<=high:
        mid = (low+high)//2
        if data[mid] == target:
            return  mid+1
        elif data[mid] > target:
            high = mid -1
        else:
         low = mid+1
    return 0
data = [1,3,4,67,6]
target = 6
a=half_search(data,target)-1
print a
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原文地址:http://www.cnblogs.com/linbinqiang/p/5287482.html