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[leetcode] 100 Same Tree

时间:2016-03-21 10:31:03      阅读:115      评论:0      收藏:0      [点我收藏+]

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Given two binary trees, write a function to check if they are equal or not.

Two binary trees are considered equal if they are structurally identical and the nodes have the same value.

递归

/**
 * Definition for a binary tree node.
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool isSameTree(TreeNode* p, TreeNode* q) {
        if(p==NULL && q==NULL) return true;
        if(p && q)
        {
            if((p->val == q->val) && isSameTree(p->left,q->left) && isSameTree(p->right,q->right)) return true;
        }
        return false;
    }
};

  

[leetcode] 100 Same Tree

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原文地址:http://www.cnblogs.com/yuchenkit/p/5300693.html

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