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link 链表反转

时间:2014-07-27 11:33:12      阅读:204      评论:0      收藏:0      [点我收藏+]

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链表反转,示例如下:
偶数个输入:a->b->c->d->e->f
偶数个输出:e->f->c->d->a->b
or
奇数个输入:a->b->c->d->e->f->g
偶数个输入:g->e->f->c->d->a->b

#include <stdio.h>
#include <malloc.h>  
#include <stdlib.h>

/************** start of stack *************/

#define STACK_SIZE 1024

char stack[STACK_SIZE];
int top = 0;

void push(char ch){
    stack[top] = ch;
    top++;
}

char pop(){
    top--;
    return stack[top];
}

int isempty(){
    return 0 == top;
}

void test_stack(){
    push(‘a‘);
    push(‘b‘);
    push(‘c‘);
    push(‘d‘);

    while(!isempty()){
        printf("pop ch: %c\n", pop());
    }
}

/************** end of stack *************/




struct _node{
    char data;
    struct _node *next;
};

typedef struct _node node, *plink;


plink init_link(){
    plink pl;
    pl = (plink)malloc(sizeof(node));
    
    // check malloc success or not
    if(NULL == pl) {
        printf("malloc memory fail...");
        return NULL;
    }
    
    // init link head
    pl->data = ‘\0‘;
    pl->next = NULL;
    
    return pl;
}

void input_data(plink pl, char data){
    plink p = pl;
    
    while(p->next){
        p = p->next;
    }
    
    plink node = NULL;
    node = (plink)malloc(sizeof(node));     // malloc a new node
    
    // add data
    if(NULL != node){
        node->data = data;
        node->next = p->next;        // last next is NULL
        p->next = node;
        p = node;                    // p point last node
    }
}

void output_link(plink pl){
    if(NULL == pl){
        printf("plink is null");
        return;
    }
    
    plink p = pl->next;    // already check pl is NULL, so here is ok
    while(NULL != p){
        printf("%c -> ", p->data);
        p = p->next;
    } 
    printf("\n\n");        
}



// push and pop stack
plink revert_link2(plink pl){
    plink p = pl;

    while(p->next){
//        printf("p->data: %c\n", p->next->data);
        if(p->next->next){
            push(p->next->next->data);
            push(p->next->data);
            p = p->next->next;
        } else {
            push(p->next->data);
            p = p->next;
        }
    }

    while(!isempty()){
        printf("%c -> ", pop());
    }
    
    printf("\n\n");

    return NULL;
}



plink revert_link(plink pl){
    if(NULL == pl){    // check link is NULL
        return NULL;
    }
    
    int link_len = 0;
    plink tmp_pl = pl->next;
    
    while(tmp_pl){    // count link count
        link_len++;
        tmp_pl = tmp_pl->next;
    }
    
    // link length is no more than two node(s)
    if(link_len <= 2){
        return pl;
    }
    
    // link length is more than two nodes
    return revert_link2(pl);
}




int main(){
    plink pl = NULL;
    
    pl = init_link();         // init link head
    
    input_data(pl, ‘a‘);      // add data
    input_data(pl, ‘b‘);
    input_data(pl, ‘c‘);
    input_data(pl, ‘d‘);
    input_data(pl, ‘e‘);
    input_data(pl, ‘f‘);
    input_data(pl, ‘g‘);
    
    output_link(pl);
    
    plink pl2 = revert_link(pl);
    
    output_link(pl2);

    return 0;
}



/****
revert_link.c


linux gcc compile
gcc revert_link.c -o revert_link && ./revert_link


output result:

a -> b -> c -> d -> e -> f -> g 
g -> e -> f -> c -> d -> a -> b

or

a -> b -> c -> d -> e -> f
e -> f -> c -> d -> a -> b


****/

间隔螺旋反转:

输入: a -> b -> c -> d -> e -> f 
输出: b -> a -> d -> c -> f -> e

plink revert_link3(plink pl){
    if(NULL == pl){
        printf("plink is null");
        return NULL;	
    }	

    plink p = pl;
    plink first = p->next;
    while(NULL != first){
        plink second = first->next;
        if(NULL != second){
            first->next = second->next;     // third node
            second->next = first;           // revert two nodes
            first = first->next;
            p->next = second;
            p = second->next;
        }
    }
    return pl;
}


link 链表反转

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原文地址:http://blog.csdn.net/ithomer/article/details/38148971

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