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leetcode:Minimum Path Sum

时间:2016-03-28 18:16:45      阅读:156      评论:0      收藏:0      [点我收藏+]

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不大懂

1、

  Given a m x n grid filled with non-negative numbers, find a path from top left to bottom right which minimizes the sum of all numbers along its path.

2、代码

  

 public int minPathSum(int[][] grid) {
       if (grid == null || grid.length == 0 || grid[0].length == 0) {
            return 0;
        }

        int M = grid.length;
        int N = grid[0].length;
        int[][] sum = new int[M][N];

        sum[0][0] = grid[0][0];
     //第一列的值,当前值加上前面和
        for (int i = 1; i < M; i++) {
            sum[i][0] = sum[i - 1][0] + grid[i][0];
        }
     //第一行的值,同理
        for (int i = 1; i < N; i++) {
            sum[0][i] = sum[0][i - 1] + grid[0][i];
        }
     //M:行数
        for (int i = 1; i < M; i++) {
      //N:列数
for (int j = 1; j < N; j++) {
          //走最短的路线,数字叫小值 sum[i][j]
= Math.min(sum[i - 1][j], sum[i][j - 1]) + grid[i][j]; } }      return sum[M - 1][N - 1]; }

 

leetcode:Minimum Path Sum

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原文地址:http://www.cnblogs.com/zilanghuo/p/5329879.html

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