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CodeForces - 417E(随机数)

时间:2016-04-23 19:39:19      阅读:142      评论:0      收藏:0      [点我收藏+]

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Time Limit: 1000MS   Memory Limit: 262144KB   64bit IO Format: %I64d & %I64u

 Status

Description

While resting on the ship after the "Russian Code Cup" a boy named Misha invented an interesting game. He promised to give his quadrocopter to whoever will be the first one to make a rectangular table of size n × m, consisting of positive integers such that the sum of the squares of numbers for each row and each column was also a square.

Since checking the correctness of the table manually is difficult, Misha asks you to make each number in the table to not exceed 108.

Input

The first line contains two integers n and m (1 ≤ n, m ≤ 100)  — the size of the table.

Output

Print the table that meets the condition: n lines containing m integers, separated by spaces. If there are multiple possible answers, you are allowed to print anyone. It is guaranteed that there exists at least one correct answer.

Sample Input

Input
1 1
Output
1
Input
1 2
Output
3 4

Source

 

#include <iostream>
#include <math.h>
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <algorithm>
using namespace std;
bool pd(int s)
{
    int k=sqrt(s);
    return k*k==s;
}
int main()
{
    int n,m,a,b,c,d,i,j;
    while(cin>>n>>m)
    {
       for (a=1;a<=100;a++)
       for (b=1;b<=100;b++)
       for (c=1;c<=100;c++)
       for (d=1;d<=100;d++)
       {
           int s1=(m-1)*a*a+b*b;
           int s2=(n-1)*a*a+c*c;
           int s3=(n-1)*b*b+d*d;
           int s4=(m-1)*c*c+d*d;
           if (pd(s1)&&pd(s2)&&pd(s3)&&pd(s4))
           goto next;
       }
       next:
       for (i=1;i<n;i++)
       {
           for (j=1;j<m;j++)
           cout<<a<<" ";
           cout<<b<<endl;
       }
       for (i=1;i<m;i++)
       cout<<c<<" ";
       cout<<d<<endl;
    }
    return 0;
}

 

CodeForces - 417E(随机数)

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原文地址:http://www.cnblogs.com/Ritchie/p/5425163.html

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