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PHP: $days = cal_days_in_month(CAL_GREGORIAN, 4, 2011); echo "返回2011-4的天数 ".$days."<br/>"; $days = date(‘t‘, strtotime("2011-4-1")); echo "返回2011-4的天数 ".$days."<br/>"; $days = date("t"); echo "当前月的天数 ".$days."<br/>";标签:
原文地址:http://www.cnblogs.com/lz20150121/p/5434491.html