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题目
给出一棵二叉树,返回其中序遍历
C++
非递归
vector<int> inorderTraversal(TreeNode *root) {
// write your code here
vector<int> vec;
stack<TreeNode*> s;
TreeNode* p;
p = root;
while (p || !s.empty())
{
while(p)
{
s.push(p);
p = p->left;
}
p = s.top();
vec.push_back(p->val);
s.pop();
p = p->right;
}
return vec;
}
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原文地址:http://www.cnblogs.com/Smallhui/p/5449014.html