1
5

1
0

Hint
hint
 

Consider the second test case:

The initial condition	   : 0 0 0 0 0 …
After the first operation  : 1 1 1 1 1 …
After the second operation : 1 0 1 0 1 …
After the third operation  : 1 0 0 0 1 …
After the fourth operation : 1 0 0 1 1 …
After the fifth operation  : 1 0 0 1 0 …

The later operations cannot change the condition of the fifth lamp any more. So the answer is 0.

#include <iostream>
#include <cmath>
using namespace std;
int main()
{
    int n;
    while(cin>>n)
    {
        double x=sqrt(n*1.0);
        cout<<(x==int(x))<<endl;

    }
    return 0;
}

AC代码2:

#include <iostream>
using namespace std;
int main()
{
    int n;
    while(cin>>n)
    {
        int sum=0;
        for(int i=1; i<=n; i++)
        {
            if(n%i==0)
                sum++;
        }

        cout<<sum%2<<endl;

    }
    return 0;
}