标签：hdu1799

循环多少次？

Time Limit: 3000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 2821    Accepted Submission(s): 1022

2
1 3
2 3

3
3

在演草纸上列表格找规律。

#include <stdio.h>
#define maxn 2002

int dp[maxn][maxn];

void count()
{
	int i, j;
	for(i = 1; i < maxn; ++i)
		dp[i][1] = i % 1007;
	for(i = 1; i < maxn; ++i)
		for(j = 2; j < maxn; ++j)
			dp[i][j] = (dp[i-1][j] + dp[i-1][j-1]) % 1007;
}

int main()
{
	int n, m, t;
	count();
	scanf("%d", &t);
	while(t--){
		scanf("%d%d", &m, &n);
		printf("%d\n", dp[n][m]);
	}
	return 0;
}

HDU1799 循环多少次？【找规律】,布布扣,bubuko.com

HDU1799 循环多少次？【找规律】

标签：hdu1799

原文地址：http://blog.csdn.net/chang_mu/article/details/38322929