


3 123 321 3 123 312
Yes. in in in out out out FINISH No. FINISHFor the first Sample Input, we let train 1 get in, then train 2 and train 3. So now train 3 is at the top of the railway, so train 3 can leave first, then train 2 and train 1. In the second Sample input, we should let train 3 leave first, so we have to let train 1 get in, then train 2 and train 3. Now we can let train 3 leave. But after that we can‘t let train 1 leave before train 2, because train 2 is at the top of the railway at the moment. So we output "No.".HintHint
题意:给出初始序列和序列a和b,和一个栈c ,a只能进c,不能回来,c只能进b,求能否达到目标并打印路径。
典型的栈,直接模拟。
#include <stdio.h>
#include <string.h>
#include <algorithm>
#include <math.h>
#include <ctype.h>
using namespace std;
typedef long long LL;
const int MAX=0x3f3f3f3f;
int n ,op[4004];
char a[2005], b[2005], c[2005];
int main()
{
while(~scanf("%d %s %s",&n,a,b)) {
int i=0,j=0,top=-1,k=0;
while(j<n) { // b里还有车没匹配
if( a[i] == b[j] ) { //a的第一辆与b直接匹配
op[k++] = 1;
op[k++] = 0;
i++,j++;
} else if( top >= 0 && c[top] == b[j]) { // 栈里的车与b匹配
op[k++] = 0;
j++,top--;
} else if(i<n) { // 都不匹配就把a里的车入栈
top++;
c[top] = a[i];
op[k++] = 1;
i++;
} else break; //a里没车了直接退出循环
}
if(j >= n) {
printf("Yes.\n");
for(int i=0;i<k;i++)
if(op[i] == 1) printf("in\n");
else printf("out\n");
} else printf("No.\n");
printf("FINISH\n");
}
return 0;
}
HDU 1022 Train Problem I (数据结构 —— 栈),布布扣,bubuko.com
HDU 1022 Train Problem I (数据结构 —— 栈)
原文地址:http://blog.csdn.net/u013923947/article/details/38334357