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POJ 2886 Who Gets the Most Candies?

时间:2014-08-04 16:59:47      阅读:325      评论:0      收藏:0      [点我收藏+]

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题目大意是:n个人围成一圈 ,每个人有一个非零数num,为正表示在他出去以后他左边第num 个人出去,否则右边第-num个人出去,给定最开始出去的人,求第m个出去的人,其中,1<=m<=n, m的约数个数在1..n中是最多的 输出这个人的名字和m的约数个数

分两步:

(1)首先求m,可以预处理求出1到maxn的所有数的约数个数,并求出数组f[p],当n==p时,f[p]表示约数个数最多的那个数;这样对每一个n,O(1)得到m;

(2)求出m以后,就是模拟了,模拟前m次出队过程,问题的关键就是如何确定下一个要出去的人。线段树是显然符合要求的,保存当前区间内实际存在的人数,然后就是简单的单点更新了,更新和查询都是logn级别的

被坑出翔的地方:题目给的数据是顺时针给的,也就是从右到左,而线段树是从左到右的,所以题目给定的方向也必须反过来,下面是代码:

bubuko.com,布布扣
  1 /**********************************************
  2 ***    Problem:
  3 ***    Author:        JKL
  4 ***    University:    CSUST
  5 ***    Team:          __Dream
  6 ***    Email:          1451108308@QQ.COM
  7 ***    My Blog:        http://www.cnblogs.com/jklongint/
  8 ***********************************************/
  9 //===================================================
 10 #include <iostream>
 11 #include <fstream>
 12 #include <sstream>
 13 #include <iomanip>
 14 #include <cstdio>
 15 #include <cstdlib>
 16 #include <cmath>
 17 #include <cassert>
 18 #include <numeric>
 19 #include <ctime>
 20 #include <algorithm>
 21 #include <cstring>
 22 #include <string>
 23 #include <vector>
 24 #include <queue>
 25 #include <map>
 26 #include <stack>
 27 #include <list>
 28 #include <set>
 29 #include <bitset>
 30 #include <deque>
 31 using namespace std;
 32 //---------------------------------------------------
 33 #define mem(a,b) memset(a,b,sizeof(a))
 34 #define GO cout<<"HelloWorld!"<<endl
 35 #define Case(x) cout<<"Case "<<x<<":"
 36 #define foru(i,n) for(int i=1; i <= n; i++)
 37 #define ford(i,n) for(int i = n; i >= 1; i--)
 38  #define fin freopen("input.txt","r",stdin);
 39  #define fout freopen("output.txt","w",stdout)
 40 #define lson  l, m, rt << 1
 41 #define rson  m + 1, r, rt << 1 | 1
 42 
 43 #define sqr(a)  ((a)*(a))
 44 #define abs(a) ((a>0)?(a):-(a))
 45 #define pii pair<int,int>
 46 
 47 #define fmax(a,b) max(a,b)
 48 #define fmin(a,b) min(a,b)
 49 #define fmax3(a,b,c)  (fmax(a,fmax(a,b)))
 50 #define fmin3(a,b,c)  (fmin(a,fmin(a,b)))
 51 
 52 #define sfi(x) scanf("%d",&x)
 53 #define sfL(x) scanf("%I64d",&x)
 54 #define sfc(x) scanf("%c",&x)
 55 #define sfd(x) scanf("%lf",&x)
 56 #define sfs(x) scanf("%s",x)
 57 #define sfii(a,b) scanf("%d%d",&a,&b)
 58 #define sfLL(a,b) scanf("%I64d%I64d",&a,&b)
 59 #define sfcc(a,b) scanf("%c%c",&a,&b)
 60 #define sfdd(a,b) scanf("%lf%lf",&a,&b)
 61 #define sfss(a,b) scanf("%s%s",a,b)
 62 
 63 #define pfi(x) printf("%d",x)
 64 #define pfL(x) printf("%I64d",x)
 65 #define pfs(x) printf("%s",x)
 66 #define pfd(x) printf("%lf",x)
 67 #define pfc(x) print("%c",x)
 68 #define newLine pfs("\n")
 69 #define space pfs(" ")
 70 
 71 //--------------------------------------------------------
 72 typedef long long LL;
 73 typedef unsigned long long ULL;
 74 typedef __int64 __LL;
 75 typedef unsigned __int64 __ULL;
 76 
 77 typedef vector<int> vi;
 78 typedef vector<LL> vL;
 79 typedef vector<string> vs;
 80 typedef set<int> si;
 81 typedef map<int,int> mii;
 82 typedef map<LL,LL> mLL;
 83 typedef map<string,int> msi;
 84 typedef map<char,int> mci;
 85 //--------------------------------------------------------
 86 const int dx[4]={1,-1,0,0};
 87 const int dy[4]={0,0,1,-1};
 88  const int day[13]={0,31,28,31,30,31,30,31,31,30,31,30,31};
 89  const int N6=1000006;
 90  const int N5=100006;
 91  const int N4=10006;
 92  const int N3=1006;
 93  const int N2=106;
 94  const int N=510009;
 95  const int MOD=1000000007;
 96  const LL LMAX=0x7fffffffffffffff;
 97  const LL IMAX=0x3fffffff;
 98  const double PI=3.14159265359;
 99 //--------------------------------------------------------
100 template< class T > T gcd(T a, T b) { return (b != 0 ? gcd<T>(b, a%b) : a); }
101 template< class T > T lcm(T a, T b) { return (a / gcd<T>(a, b) * b); }
102 
103 //------------------------------------------------------------
104 struct TreeNode{
105     int  cnt;
106 };
107 //=================================================================
108 TreeNode tree[N << 2];
109 int n, k, a[N],cnt[N + 2], ans, max0[N + 2], cc[N + 2];
110 char s[N][15];
111 void init()
112 {
113     for(int i = 1; i <= N; i++){
114         for(int j = 1; j * i <= N ; j++)
115             cnt[j * i]++;
116     }
117     foru(i, N){
118         if(max0[i-1] < cnt[i]){
119             max0[i] = cnt[i];
120             cc[i] = i;
121         }
122         else{
123              max0[i] = max0[i - 1];
124              cc[i] = cc[i - 1];
125         }
126     }
127 }
128 void PushUP(int rt)
129 {
130     tree[rt].cnt = tree[rt << 1].cnt + tree[rt << 1 | 1].cnt;
131 }
132 void build(int l, int r, int rt)
133 {
134     if(l == r){
135         tree[rt].cnt = 1;
136         return;
137     }
138     int m = (l + r) >> 1;
139     build(lson);
140     build(rson);
141     PushUP(rt);
142 }
143 int query(int p, int l, int r, int rt)
144 {
145     if(l == r){
146         tree[rt].cnt = 0;
147         return l;
148     }
149     int m = (l + r) >> 1, cnt = tree[rt << 1].cnt, tmp;
150     if(p <= cnt) tmp = query(p, lson);
151     else tmp = query(p - cnt, rson);
152     PushUP(rt);
153     return tmp;
154 }
155 int getNext(int pos, int cnt)
156 {
157     int total = tree[1].cnt, mark;
158     if(total == 0) return 0;
159     mark = cnt > 0 ? 1 : -1;
160     if(cnt > 0)cnt %= total;else cnt = -((-cnt) % total);
161     if(mark > 0)return (pos - cnt + total -1) % total + 1;
162      else return (pos -cnt -2) % total + 1;
163 }
164 int main()
165 {
166     //fin;fout;
167     init();
168     while( ~ sfii(n, k)){
169         build(1, n, 1);
170         foru(i, n)sfs(s[i]), sfi(a[i]);
171         int pos = k, c = cc[n], out;
172         foru(i, c){
173             out = query(pos, 1, n, 1);
174             pos = getNext(pos, -a[out]);
175         }
176         pfs(s[out]);space;pfi(cnt[c]);newLine;
177     }
178     return 0;
179 }
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POJ 2886 Who Gets the Most Candies?,布布扣,bubuko.com

POJ 2886 Who Gets the Most Candies?

标签:style   blog   http   color   os   io   数据   for   

原文地址:http://www.cnblogs.com/jklongint/p/3890175.html

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