Given two binary strings, return their sum (also a binary string).
For example,
a = "11"
b = "1"
Return "100"
.
class Solution { public: string addBinary(string a, string b) { size_t na = a.size(); int nb = b.size(); int n = na > nb ? na : nb; string result(n,'0'); int ch= 0; int i= n-1,ia=na-1,ib=nb-1; for(;ia >=0 && ib >= 0; ){ int re = a[ia]-'0'+b[ib]-'0' + ch; ch=re/2; result[i]=re%2+'0'; ia--; ib--; i--; } //int re = a[0]+b[0]-'0'+'0'+ch; while(ia >=0){ int re = a[ia]-'0' +ch; ch = re/2; result[i] = re%2+'0'; ia--; i--; } while(ib >=0){ int re = b[ib]-'0'+ch; ch = re/2; ib--; result[i]= re%2+'0'; i--; } if(ch){ result.insert(0,"1"); } return result; } };
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原文地址:http://blog.csdn.net/qq112928/article/details/38377267