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237. Delete Node in a Linked List

时间:2016-06-28 20:33:04      阅读:137      评论:0      收藏:0      [点我收藏+]

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question:

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value 3, the linked list should become 1 -> 2 -> 4 after calling your function.

answer:

把node->next值赋给node,再删除node->next,也就是让node指向node->next的下一位

 

/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    void deleteNode(ListNode* node) {
        if(node!=NULL){
            node->val=node->next->val;
            node->next=node->next->next;
            return;
        }
    }
};

 

237. Delete Node in a Linked List

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原文地址:http://www.cnblogs.com/Reindeer/p/5624703.html

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