标签:des style blog color java os io strong
归并排序求逆序数,然后ans-k与0取一个最大值就可以了。
也可以用树状数组做,比赛的时候可能姿势不对,树状数组wa了、、
3 1 2 2 1 3 0 2 2 1
1 2
#include <algorithm>
#include <iostream>
#include <stdlib.h>
#include <string.h>
#include <iomanip>
#include <stdio.h>
#include <string>
#include <queue>
#include <cmath>
#include <stack>
#include <map>
#include <set>
#define eps 1e-12
///#define M 1000100
#define LL __int64
///#define LL long long
///#define INF 0x7ffffff
#define INF 0x3f3f3f3f
#define PI 3.1415926535898
#define zero(x) ((fabs(x)<eps)?0:x)
using namespace std;
const int maxn = 10010000;
int num[maxn];
LL ans;
int tmp[maxn];
void Sell(int l, int mid, int r)
{
int i = l;
int j = mid+1;
int k = 0;
while(i <= mid && j <= r)
{
if(num[i] > num[j])
{
tmp[k++] = num[j++];
ans += mid-i+1;
}
else tmp[k++] = num[i++];
}
while(i <= mid)
tmp[k++] = num[i++];
while(j <= r)
tmp[k++] = num[j++];
for(int i = 0; i < k; i++)
num[i+l] = tmp[i];
}
void Sort(int l, int r)
{
if(l < r)
{
int mid = (l+r)/2;
Sort(l, mid);
Sort(mid+1, r);
Sell(l, mid, r);
}
}
int main()
{
int n, k;
while(cin >>n>>k)
{
ans = 0;
for(int i = 0;i < n; i++) scanf("%d",&num[i]);
Sort(0, n-1);
cout<<max(0LL, ans-k)<<endl;
}
return 0;
}
HDU 4911 Inversion(归并排序求逆序数),布布扣,bubuko.com
标签:des style blog color java os io strong
原文地址:http://blog.csdn.net/xu12110501127/article/details/38396323