uva 437 The Tower of Babylon（动态规划 嵌套矩形问题最长路）

标签：动态规划

有思路就去做，要相信自己

多处理更复杂的情况，你就不觉得现在复杂了

#include<cstdio>
#include<cstring>
#include<algorithm>
using namespace std;
typedef long long ll;
struct soli
{
    ll a,b,c;
}s[40];
int n;
ll d[40][3];
int vis[40][3];
ll answer[40][3];

ll dp(int s1,int s2)
{
    if(vis[s1][s2])
        return d[s1][s2];
    vis[s1][s2]=1;
    ll& ans=d[s1][s2];
    ll temp1,temp2;
    if(s2==0){temp1=s[s1].b;temp2=s[s1].c;ans=s[s1].a;}
    if(s2==1){temp1=s[s1].a;temp2=s[s1].c;ans=s[s1].b;}
    if(s2==2){temp1=s[s1].a;temp2=s[s1].b;ans=s[s1].c;}
    ll temp=ans;
    for(int i=1;i<=n;i++)
    {
        for(int j=0;j<=2;j++)
        {
            if(j==0)
            {
                if((s[i].b<temp1&&s[i].c<temp2)||(s[i].b<temp2&&s[i].c<temp1))
                {
                    ans=max(ans,dp(i,j)+temp);
                }
            }
            if(j==1)
            {
                if((s[i].a<temp1&&s[i].c<temp2)||(s[i].a<temp2&&s[i].c<temp1))
                {
                    ans=max(ans,dp(i,j)+temp);
                }
            }
            if(j==2)
            {
                if((s[i].b<temp1&&s[i].a<temp2)||(s[i].b<temp2&&s[i].a<temp1))
                {
                    ans=max(ans,dp(i,j)+temp);
                }
            }
        }
    }
    return ans;
}
int main()
{
    int kase=0;
    while(scanf("%d",&n)!=EOF)
    {
        if(n==0) break;
        kase++;
        ll a1,a2,a3;
        memset(s,0,sizeof(s));
        for(int i=1;i<=n;i++)
        {
            scanf("%I64d%I64d%I64d",&a1,&a2,&a3);
            s[i].a=a1;
            s[i].b=a2;
            s[i].c=a3;
        }
        memset(answer,0,sizeof(answer));
        for(int i=1;i<=n;i++)
        {
            for(int j=0;j<=2;j++)
            {
                memset(d,0,sizeof(d));
                memset(vis,0,sizeof(vis));
                answer[i][j]=dp(i,j);
            }
        }
        ll max_=0;
        for(int i=1;i<=n;i++)
        {
            for(int j=0;j<=2;j++)
            {
                max_=max(max_,answer[i][j]);
            }
        }
        printf("Case %d: maximum height = %I64d\n",kase,max_);
    }
    return 0;
}

uva 437 The Tower of Babylon（动态规划 嵌套矩形问题最长路）,布布扣,bubuko.com

uva 437 The Tower of Babylon（动态规划 嵌套矩形问题最长路）

标签：动态规划

原文地址：http://blog.csdn.net/u013382399/article/details/38421223