标签:线段树
Time Limit: 9000/3000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 38359 Accepted Submission(s): 15178
5 6 1 2 3 4 5 Q 1 5 U 3 6 Q 3 4 Q 4 5 U 2 9 Q 1 5
5 6 5 9HintHuge input,the C function scanf() will work better than cin
本来看到找最大直接用rmq的,一写发现rmq更新耗时太大了。。。。。用线段树模板稍微改一下就过了,把和改成最大就行
#include<iostream>
#include<cstdio>
#include<cmath>
#include<algorithm>
#define maxn 200001
using namespace std;
const int MX=200001;
int n,t;
int tree[MX*4];
int max1(int a,int b)
{
return a>b?a:b;
}
void up(int index)
{
tree[index]=max1(tree[index<<1],tree[index<<1|1]);
}
void create(int index,int l,int r)
{
if(l==r)
{
scanf("%d",&tree[index]);return;
}
int mind=(l+r)/2;
create(index<<1,l,mind);
create(index<<1|1,mind+1,r);
up(index);
}
int getse(int index,int s,int e,int l,int r)
{
if(s<=l&&r<=e)
return tree[index];
int ans=0;
int mind=(r+l)/2;
if(s<=mind)
ans=max1(ans,getse(index<<1,s,e,l,mind));
if(e>mind)
ans=max1(ans,getse(index<<1|1,s,e,mind+1,r));
return ans;
}
void update(int index,int p,int v,int l,int r)
{
if(l==r){
tree[index]=max1(tree[index],v);return;
}
int mind=(r+l)/2;
if(p<=mind) update(index<<1,p,v,l,mind);
else update(index<<1|1,p,v,mind+1,r);
up(index);
}
int main()
{
while(scanf("%d%d",&n,&t)!=EOF)
{
create(1,1,n);
int a,b;
char g;
while(t--)
{
getchar();
scanf("%c%d%d",&g,&a,&b);
if(g=='Q')
{
printf("%d\n", getse(1,a,b,1,n));
}else{
update(1,a,b,1,n);
}
}
}
return 0;
}
HDU1754I Hate It,布布扣,bubuko.com
标签:线段树
原文地址:http://blog.csdn.net/fljssj/article/details/38470821