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leetcode 104

时间:2016-09-13 13:29:52      阅读:150      评论:0      收藏:0      [点我收藏+]

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104. Maximum Depth of Binary Tree

Given a binary tree, find its maximum depth.

The maximum depth is the number of nodes along the longest path from the root node down to the farthest leaf node.

求二叉树的最大深度。

采用递归实现:

(1)如果二叉树为空,二叉树的深度为0
(2)如果二叉树不为空,二叉树的深度 = max(左子树深度, 右子树深度) + 1

 

代码如下:

 

 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     int maxDepth(TreeNode* root) {
13         if(root == NULL)
14         {
15             return 0;
16         }
17         int left = maxDepth(root->left);
18         int right = maxDepth(root->right);
19         
20         return left > right ? (left + 1) : (right + 1);
21     }
22 };

 

leetcode 104

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原文地址:http://www.cnblogs.com/shellfishsplace/p/5867963.html

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