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Given an array S of n integers, find three integers in S such that the sum is closest to a given number, target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
For example, given array S = {-1 2 1 -4}, and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
public int ThreeSumClosest(int[] nums, int target) { Array.Sort(nums); int size = nums.Count(); int res = Int32.MaxValue; for(int i =0;i< size-1;i++) { int last = Int32.MaxValue; int dif = target - nums[i]; int left = i+1; int right = size-1; while(left < right) { int a = nums[left] + nums[right] - dif; if(a==0) return target; if(Math.Abs(a)< last ) { res = Math.Abs(a)>Math.Abs(res) ?res :a; last = Math.Abs(a); } if(a<0) left++; else right--; } } return res+target; }
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原文地址：http://www.cnblogs.com/renyualbert/p/5904861.html
