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题目链接:
Time Limit: 6000/3000 MS (Java/Others) Memory Limit: 65536/65536 K (Java/Others)
Total Submission(s): 813 Accepted Submission(s): 379
#include <bits/stdc++.h>
using namespace std;
typedef long long LL;
const int maxn=1e5+10;
const LL mod=1e9+7;
LL dp[maxn],num,sum[maxn];
map<int,LL>mp;
int n,a[maxn];
int main()
{
int t;
scanf("%d",&t);
while(t--)
{
mp.clear();
scanf("%d",&n);
for(int i=1;i<=n;i++)scanf("%d",&a[i]);
sum[1]=a[1];num=1;mp[a[1]]=1;
for(int i=2;i<=n;i++)
{
dp[i]=(a[i]+sum[i-1])%mod;
dp[i]=(dp[i]+(num-mp[a[i]]+mod)%mod*a[i])%mod;
mp[a[i]]=(mp[a[i]]+num+1)%mod;
num=(num*2+1)%mod;
sum[i]=(sum[i-1]+dp[i])%mod;
}
printf("%lld\n",sum[n]);
}
return 0;
}
hdu-5496 Beauty of Sequence(递推)
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原文地址:http://www.cnblogs.com/zhangchengc919/p/5920837.html