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1.词法分析程序的功能
从左至右地对源程序进行扫描,按照语言的词法规则识别各类单词,并产生相应单词的属性字
2.符号与种别码对照表
| 单词符号 | 种别码 | 单词符号 | 种别码 | 
| begin | 1 | : | 17 | 
| if | 2 | := | 18 | 
| then | 3 | > | 20 | 
| while | 4 | <> | 21 | 
| do | 5 | <= | 22 | 
| end | 6 | < | 23 | 
| letter(letter|digit)* | 10 | >= | 24 | 
| digit digit* | 11 | = | 25 | 
| * | 13 | ; | 26 | 
| / | 14 | ( | 27 | 
| + | 15 | ) | 28 | 
| - | 16 | # | 0 | 
3.用文法描述词法规则
A→aa|Aaa 以aa开头,每次循环增加aa
4.已完成代码及运行结果截图
#include<stdio.h>
#include<string.h>
#include<iostream.h>
char prog[80],token[8];
char ch;
int syn,p,m=0,n,row,sum=0;
char *rwtab[6]={"begin","if","then","while","do","end"};
 
void scaner()
{
    for(n=0;n<8;n++) token[n]=NULL;
    ch=prog[p++];
    while(ch==‘ ‘)
    {
        ch=prog[p];
        p++;
    }
    if((ch>=‘a‘&&ch<=‘z‘)||(ch>=‘A‘&&ch<=‘Z‘)) 
    {
        m=0;
        while((ch>=‘0‘&&ch<=‘9‘)||(ch>=‘a‘&&ch<=‘z‘)||(ch>=‘A‘&&ch<=‘Z‘))
        {
            token[m++]=ch;
            ch=prog[p++];
        }
        token[m++]=‘\0‘;
        p--;
        syn=10;
        for(n=0;n<6;n++)   
            if(strcmp(token,rwtab[n])==0)
            {
                syn=n+1;
                break;
            }
    }
    else if((ch>=‘0‘&&ch<=‘9‘)) 
    {
        {
            sum=0;
            while((ch>=‘0‘&&ch<=‘9‘))
            {
                sum=sum*10+ch-‘0‘;
                ch=prog[p++];
            }
        }
        p--;
        syn=11;
        if(sum>32767)
            syn=-1;
    }
    else switch(ch)  
    {
        case‘<‘:m=0;token[m++]=ch;
            ch=prog[p++];
            if(ch==‘>‘)
            {
                syn=21;
                token[m++]=ch;
            }
            else if(ch==‘=‘)
            {
                syn=22;
                token[m++]=ch;
            }
            else
            {
                syn=23;
                p--;
            }
            break;
        case‘>‘:m=0;token[m++]=ch;
            ch=prog[p++];
            if(ch==‘=‘)
            {
                syn=24;
                token[m++]=ch;
            }
            else
            {
                syn=20;
                p--;
            }
            break;
        case‘:‘:m=0;token[m++]=ch;
            ch=prog[p++];
            if(ch==‘=‘)
            {
                syn=18;
                token[m++]=ch;
            }
            else
            {
                syn=17;
                p--;
            }
            break;
        case‘*‘:syn=13;token[0]=ch;break;
        case‘/‘:syn=14;token[0]=ch;break;
        case‘+‘:syn=15;token[0]=ch;break;
        case‘-‘:syn=16;token[0]=ch;break;
        case‘=‘:syn=25;token[0]=ch;break;
        case‘;‘:syn=26;token[0]=ch;break;
        case‘(‘:syn=27;token[0]=ch;break;
        case‘)‘:syn=28;token[0]=ch;break;
        case‘#‘:syn=0;token[0]=ch;break;
        case‘\n‘:syn=-2;break;
        default: syn=-1;break;
    }
}
int main()
{
    p=0;
    row=1;
    cout<<"please input string:"<<endl;
    do
    {
        cin.get(ch);
        prog[p++]=ch;
    }
    while(ch!=‘#‘);
    p=0;
    do
    {
        scaner();
        switch(syn)
        {
        case 11: cout<<"("<<syn<<","<<sum<<")"<<endl; break;  
        case -1: cout<<"Error in row "<<row<<"!"<<endl; break;
        case -2: row=row++;break;
        default: cout<<"("<<syn<<","<<token<<")"<<endl;break;
        }
    }
    while (syn!=0);
}

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原文地址:http://www.cnblogs.com/wha000/p/5924740.html