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LeetCode 397. Integer Replacement

时间:2016-10-01 22:06:17      阅读:325      评论:0      收藏:0      [点我收藏+]

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397. Integer Replacement

 
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  • Difficulty: Easy

 

Given a positive integer n and you can do operations as follow:

 

  1. If n is even, replace n with n/2.
  2. If n is odd, you can replace n with either n + 1 or n - 1.

 

What is the minimum number of replacements needed for n to become 1?

 

Example 1:

Input:
8

Output:
3

Explanation:
8 -> 4 -> 2 -> 1

 

Example 2:

Input:
7

Output:
4

Explanation:
7 -> 8 -> 4 -> 2 -> 1
or
7 -> 6 -> 3 -> 2 -> 1

 

 

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这个题目没思路,参考了别人的想法  网址:https://discuss.leetcode.com/topic/58334/a-couple-of-java-solutions-with-explanations

class Solution {
public:
    int integerReplacement(int n) {
        if(INT_MAX==n)return 32;   //INT_MAX是个特殊值,如果加1就越界了
//我们也可以用long long 类型的数令它等于n,如 long long N=n;然后把下面的n替换成N即可
int c = 0; while (n != 1) { if ((n & 1) == 0) { n /= 2; } else if (n == 3 || ((n) & (1<<1)) == 0) { //留意后两位 奇数是最后一位是1 如果倒数第二位是0那么减1 使得1的位数更少 --n; } else { ++n; } ++c; } return c; } };

 

LeetCode 397. Integer Replacement

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原文地址:http://www.cnblogs.com/csudanli/p/5926307.html

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