Anagrams

标签：数据结构   算法   

Given an array of strings, return all groups of strings that are anagrams.

Note: All inputs will be in lower-case.

public class Solution {
    public List<String> anagrams(String[] strs) {
        List<String> result=new LinkedList<String>();
        Map<String,LinkedList<String>> map=new HashMap<String,LinkedList<String>>();
        if(strs==null || strs.length==0) return result;
        for(int i=0;i<strs.length;i++){
            char []arr=strs[i].toCharArray();
            Arrays.sort(arr);
            String s=new String(arr);
            
            if(map.containsKey(s)){
                map.get(s).add(strs[i]);
            }
            else{
                LinkedList<String> list=new LinkedList<String>();
                list.add(strs[i]);
                map.put(s,list);
            }
        }
        Set<String> set=map.keySet();
        for(String s : set){
            if(map.get(s).size()>1){
                result.addAll(map.get(s));
            }
        }
        return result;
    }
}

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Anagrams

标签：数据结构   算法   

原文地址：http://blog.csdn.net/dutsoft/article/details/38562597