码迷,mamicode.com
首页 > 其他好文 > 详细

441. 硬币楼梯 Arranging Coins

时间:2017-02-28 00:35:52      阅读:201      评论:0      收藏:0      [点我收藏+]

标签:pre   sum   base   over   where   color   lan   href   code   

You have a total of n coins that you want to form in a staircase shape, where every k-th row must have exactly k coins.

Given n, find the total number of full staircase rows that can be formed.

n is a non-negative integer and fits within the range of a 32-bit signed integer.

Example 1:

n = 5

The coins can form the following rows:
¤
¤ ¤
¤ ¤

Because the 3rd row is incomplete, we return 2.

Example 2:

n = 8

The coins can form the following rows:
¤
¤ ¤
¤ ¤ ¤
¤ ¤

Because the 4th row is incomplete, we return 3.

题意:给出n,返回可以组成的完整楼梯的层数

sum = (1+x)*x/2

这里就是要求 sum <= n 了。我们反过来求层数x。如果直接开方来求会存在错误,必须因式分解求得准确的x值:

(1+x)*x/2 <= n 
x + x*x <= 2*n 
4*x*x + 4*x <= 8*n 
(2*x + 1)*(2*x + 1) - 1 <= 8*n 
x <= (sqrt(8*n + 1) - 1) / 2

其中Math.sqrt()是求平方根的函数。这样我们就求出了x,最后要记得强制转换为int型数。


  1. static public int ArrangingCoins(int n) {
  2. return (int)((Math.Sqrt(8 * (long)n + 1) - 1) / 2);
  3. }





441. 硬币楼梯 Arranging Coins

标签:pre   sum   base   over   where   color   lan   href   code   

原文地址:http://www.cnblogs.com/xiejunzhao/p/73abac075151f1abc87d70f56d0f2211.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!