码迷,mamicode.com
首页 > 其他好文 > 详细

path-sum

时间:2017-03-08 13:03:14      阅读:157      评论:0      收藏:0      [点我收藏+]

标签:false   pre   add   return   and   ini   values   turn   rmi   

题目描述:

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree andsum = 22,

              5
             /             4   8
           /   /           11  13  4
         /  \              7    2      1

return true, as there exist a root-to-leaf path5->4->11->2which sum is 22.

/**
 * Definition for binary tree
 * struct TreeNode {
 *     int val;
 *     TreeNode *left;
 *     TreeNode *right;
 *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 * };
 */
class Solution {
public:
    bool hasPathSum(TreeNode *root, int sum) {
        if(!root) return false;
        
        if(root->left == NULL && root->right == NULL){
            if(root->val == sum)
                return true;
            else 
                return false;       
        }
        
        bool res = hasPathHelp(root,sum,0);
        return res;
    }
    
    bool hasPathHelp(TreeNode *root,int sum,int curSum){
        if(!root)    return false;
        
        if(root->left == NULL && root->right == NULL){
            if(curSum + root->val == sum)
                return true;
            else 
                return false;
        }
        
        return hasPathHelp(root->left,sum,curSum+root->val)||hasPathHelp(root->right,sum,curSum+root->val);
    }
};

 

path-sum

标签:false   pre   add   return   and   ini   values   turn   rmi   

原文地址:http://www.cnblogs.com/xiuxiu55/p/6518625.html

(0)
(0)
   
举报
评论 一句话评论(0
登录后才能评论!
© 2014 mamicode.com 版权所有  联系我们:gaon5@hotmail.com
迷上了代码!