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洛谷——P2871 [USACO07DEC]手链Charm Bracelet

时间:2017-04-16 11:57:48      阅读:194      评论:0      收藏:0      [点我收藏+]

标签:code   pie   available   targe   traints   with   oss   print   org   

https://www.luogu.org/problem/show?pid=2871

题目描述

Bessie has gone to the mall‘s jewelry store and spies a charm bracelet. Of course, she‘d like to fill it with the best charms possible from the N (1 ≤ N ≤ 3,402) available charms. Each charm i in the supplied list has a weight Wi (1 ≤ Wi ≤ 400), a ‘desirability‘ factor Di (1 ≤ Di ≤ 100), and can be used at most once. Bessie can only support a charm bracelet whose weight is no more than M (1 ≤ M ≤ 12,880).

Given that weight limit as a constraint and a list of the charms with their weights and desirability rating, deduce the maximum possible sum of ratings.

有N件物品和一个容量为V的背包。第i件物品的重量是c[i],价值是w[i]。求解将哪些物品装入背包可使这些物品的重量总和不超过背包容量,且价值总和最大。

输入输出格式

输入格式:

 

  • Line 1: Two space-separated integers: N and M

  • Lines 2..N+1: Line i+1 describes charm i with two space-separated integers: Wi and Di

 

输出格式:

 

  • Line 1: A single integer that is the greatest sum of charm desirabilities that can be achieved given the weight constraints

 

输入输出样例

输入样例#1:
4 6
1 4
2 6
3 12
2 7
输出样例#1:
23


 1 #include <algorithm>
 2 #include <iostream>
 3 #include <cstdio>
 4 
 5 using namespace std;
 6 
 7 int n,m,w[120053],val[120053];
 8 int f[120053];
 9 
10 int main()
11 {
12     scanf("%d%d",&n,&m);
13     for(int i=1;i<=n;i++)
14         scanf("%d%d",&w[i],&val[i]);
15     for(int i=1;i<=n;i++)
16         for(int V=m;V>=w[i];V--)
17             f[V]=max(f[V],f[V-w[i]]+val[i]);
18     printf("%d",f[m]);
19     return 0;
20 }

 

洛谷——P2871 [USACO07DEC]手链Charm Bracelet

标签:code   pie   available   targe   traints   with   oss   print   org   

原文地址:http://www.cnblogs.com/Shy-key/p/6718316.html

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