标签：oid math tin ann eof pre void nal int
题意：略。
析：答案就是32^n。
代码如下：
import java.math.BigInteger;
import java.util.Scanner;
public class Main{
public static final int maxn = 3000 + 5;
public static BigInteger []ans;
public static void main(String[] args){
Scanner cin = new Scanner(System.in);
int T = cin.nextInt();
ans = new BigInteger[maxn];
ans[0] = BigInteger.ONE;
for(int i = 1; i <= 3000; ++i)
ans[i] = ans[i-1].multiply(BigInteger.valueOf(32));
for(int kase = 1; kase <= T; ++kase){
int n = cin.nextInt();
System.out.println("Case #" + kase + ": " + ans[n]);
}
}
}
标签：oid math tin ann eof pre void nal int
原文地址：http://www.cnblogs.com/dwtfukgv/p/6786343.html
