100 10 20
100 10 50

Yes
No

#include<iostream>
#include<cstdio>
#include<string>
#include<cstring>
#include<queue>
#include<cmath>
const double pi = acos(-1);
using namespace std;
int main()
{
    double R,v1,v2;
    while(cin>>R>>v1>>v2)
    {
        double r=v1*R/v2;
        if((R-r)/v1<pi*R/v2)
            printf("Yes\n");
        else
            printf("No\n");
    }
    return 0;
}