标签:iss ssi not lua 快速幂 art please scan out
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 131072/131072 K (Java/Others)
Total Submission(s): 1107 Accepted Submission(s): 443
1 #include <stdio.h> 2 long long kuaisumi(long long a,int b) 3 { 4 long long c=1,base=a; 5 while(b) 6 { 7 if(b&1) 8 { 9 c=c*a%1000000007; 10 } 11 a=a*a%1000000007; 12 b>>=1; 13 } 14 return c; 15 } 16 int main() 17 { 18 int t,a,b,i,c; 19 long long sum; 20 scanf("%d",&t); 21 while(t--) 22 { 23 sum=0; 24 scanf("%d%d",&a,&b); 25 for(i=1;i<=a;i++) 26 { 27 c=kuaisumi(i,b); 28 sum=(sum+c)%1000000007; 29 } 30 printf("%lld\n",sum); 31 } 32 return 0; 33 }
HDU - 6027 Easy Summation(快速幂)解题
标签:iss ssi not lua 快速幂 art please scan out
原文地址:http://www.cnblogs.com/lyf0031/p/7204864.html