标签:article div2 sdn tle find 倒数第k个节点 gen src 注意
/*
struct ListNode {
int val;
struct ListNode *next;
ListNode(int x) :
val(x), next(NULL) {
}
};*/
class Solution {
public:
ListNode* FindKthToTail(ListNode* pListHead, unsigned int k) {
int len=0;
ListNode *p=pListHead;
while(p!=NULL) {
len++;//算出链表长度
p=p->next;
}
if(k>len || k<0) return NULL;//两种特殊情况
int i=1; //设置一个变量
p=pListHead;//p重置为起点
while(i<len-k+1) {//直到整数第len(list)-k个位置,进行最后一层循环,到达
p=p->next;
i++;
}
return p;
}
};
http://blog.csdn.net/hhh3h/article/details/20832387
另一种思路:
class Solution {
public:
ListNode* FindKthToTail(ListNode* p_head, unsigned int k)
{//找到链表的倒数第K个节点
//if(k==0)特殊处理,k小于链表长度,特殊处理
if (k==0 || p_head == nullptr)
return nullptr;
ListNode* first = p_head;
ListNode* second = p_head;
for (int i = 0; i < k - 1; i++) {
if(first->next== nullptr) return nullptr;
first = first->next;
}
while (first->next != nullptr)
{
first = first->next;
second = second->next;
}
return second;
}
};
标签:article div2 sdn tle find 倒数第k个节点 gen src 注意
原文地址:http://www.cnblogs.com/dd2hm/p/7291570.html