标签:output lin http flow 二叉树 ret ica arch elf
Given a Binary Search Tree and a target number, return true if there exist two elements in the BST such that their sum is equal to the given target.
Example 1:
Input: 5 / 3 6 / \ 2 4 7 Target = 9 Output: True
Example 2:
Input: 5 / 3 6 / \ 2 4 7 Target = 28 Output: False
# Definition for a binary tree node.# class TreeNode(object):# def __init__(self, x):# self.val = x# self.left = None# self.right = Noneclass Solution(object):def findTarget(self, root, k):""":type root: TreeNode:type k: int:rtype: bool"""if (not root):return Falses = set()queue = [root]while (queue):node = queue.pop(0)s.add(node.val)if(node.left):queue.append(node.left)if(node.right):queue.append(node.right)for num in s:if k - num in s and 2 * (k - num) != k:return Truereturn False
653. Two Sum IV - Input is a BST 两个数的和,输入为平衡二叉树
标签:output lin http flow 二叉树 ret ica arch elf
原文地址:http://www.cnblogs.com/xiejunzhao/p/7295873.html