标签:cpp style ring cto unsigned sign 最大的 std inf
题意:给定K个整数的序列{ N1, N2, ..., NK },其任意连续子序列可表示为{ Ni, Ni+1, ...,Nj },其中 1 <= i <= j <= K。最大连续子序列是所有连续子序列中元素和最大的一个,例如给定序列{ -2, 11, -4, 13, -5, -2 },其最大连续子序列为{ 11, -4, 13 },最大和为20。在今年的数据结构考卷中,要求编写程序得到最大和,现在增加一个要求,即还需要输出该子序列的第一个和最后一个元素。
#include<cstdio>
#include<cstring>
#include<cstdlib>
#include<cctype>
#include<cmath>
#include<iostream>
#include<sstream>
#include<iterator>
#include<algorithm>
#include<string>
#include<vector>
#include<set>
#include<map>
#include<stack>
#include<deque>
#include<queue>
#include<list>
#define lowbit(x) (x & (-x))
const double eps = 1e-8;
inline int dcmp(double a, double b){
if(fabs(a - b) < eps) return 0;
return a > b ? 1 : -1;
}
typedef long long LL;
typedef unsigned long long ULL;
const int INT_INF = 0x3f3f3f3f;
const int INT_M_INF = 0x7f7f7f7f;
const LL LL_INF = 0x3f3f3f3f3f3f3f3f;
const LL LL_M_INF = 0x7f7f7f7f7f7f7f7f;
const int dr[] = {0, 0, -1, 1, -1, -1, 1, 1};
const int dc[] = {-1, 1, 0, 0, -1, 1, -1, 1};
const int MOD = 1e9 + 7;
const double pi = acos(-1.0);
const int MAXN = 10000 + 10;
const int MAXT = 10000 + 10;
using namespace std;
int a[MAXN];
int main(){
int K;
while(scanf("%d", &K) == 1){
if(K == 0) return 0;
for(int i = 0; i < K; ++i){
scanf("%d", &a[i]);
}
int st, ed, sum, ans, tmpst;
st = ed = sum = tmpst = 0;
ans = -1;
bool ok = false;
for(int i = 0; i < K; ++i){
if(sum < 0){
sum = a[i];
tmpst = i;
}
else{
sum += a[i];
}
if(sum > ans){
ok = true;
ans = sum;
st = tmpst;
ed = i;
}
}
if(!ok){
printf("0 %d %d\n", a[0], a[K - 1]);
}
else{
printf("%d %d %d\n", ans, a[st], a[ed]);
}
}
return 0;
}
标签:cpp style ring cto unsigned sign 最大的 std inf
原文地址:http://www.cnblogs.com/tyty-Somnuspoppy/p/7340668.html