标签：style blog http color io ar strong for div
Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.
Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?
1 public class Solution { 2 public void setZeroes(int[][] matrix) { 3 if(matrix == null || matrix.length == 0 || matrix[0].length == 0) return; 4 int row = 0, col = 0; 5 boolean sig = true; 6 for(int i = 0; i < matrix.length; i ++){ 7 for(int j = 0; j < matrix[0].length; j ++){ 8 if(matrix[i][j] == 0){ 9 if(sig){ 10 row = i; 11 col = j; 12 sig = false; 13 } else { 14 matrix[row][j] = 0; 15 matrix[i][col] = 0; 16 } 17 } 18 } 19 } 20 if(sig) return; 21 for(int i = 0; i < matrix.length; i ++){ 22 for(int j = 0; j < matrix[0].length; j ++){ 23 if((matrix[row][j] == 0 || matrix[i][col] == 0) && i != row && j != col) matrix[i][j] = 0; 24 } 25 } 26 for(int i = 0; i < matrix.length; i ++){ 27 matrix[i][col] = 0; 28 } 29 for(int j = 0; j < matrix[0].length; j ++){ 30 matrix[row][j] = 0; 31 } 32 } 33 }
标签：style blog http color io ar strong for div
原文地址：http://www.cnblogs.com/reynold-lei/p/3957170.html
