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ACM HDU 1091

时间:2017-09-20 23:30:05      阅读:371      评论:0      收藏:0      [点我收藏+]

标签:min   acm   for   and   integer   int   整数   void   ane   

A+B for Input-Output Practice (III)

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 117430    Accepted Submission(s): 62074


Problem Description
Your task is to Calculate a + b.
 

 

Input
Input contains multiple test cases. Each test case contains a pair of integers a and b, one pair of integers per line. A test case containing 0 0 terminates the input and this test case is not to be processed.
 

 

Output
For each pair of input integers a and b you should output the sum of a and b in one line, and with one line of output for each line in input. 
 

 

Sample Input
1 5 10 20 0 0
 

 

Sample Output
6 30
 
 
解题思路:输入A,B两个整数,求和,当A和B都为0的时候结束。注意判断EOF。
代码如下
int main(void)
{
    int a, b, n;
    while (scanf_s("%d %d", &a, &b) != EOF)
    {
        n = 0;
        n = a + b;
        if (n == 0)
            break;
        else
        printf("%d\n", n);
    }
    return 0;
}

ACM HDU 1091

标签:min   acm   for   and   integer   int   整数   void   ane   

原文地址:http://www.cnblogs.com/WLHBlog/p/7565285.html

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