标签:length r++ substring mic ges turn str1 longest public
Brutal Force: O(n^2)
public class Solution {
    public String longestPalindrome(String s) {
        String maxPal="";
        for(int i=0;i<s.length();i++)
        {
            String str1=lenofPal(i, i, s);
            if(str1.length()>maxPal.length())
                maxPal=str1;
            String str2=lenofPal(i, i+1, s);
            if(str2.length()>maxPal.length())
                maxPal=str2;
        }
        return maxPal;
    }
    private String lenofPal(int l, int r, String s)
    {
        while(l>=0&&r<s.length()&&s.charAt(l)==s.charAt(r))
        {
            l--;
            r++;
        }
        return s.substring(l+1,r);
    }
}
Manacher: O(n)
5. Longest Palindromic Substring
标签:length r++ substring mic ges turn str1 longest public
原文地址:http://www.cnblogs.com/asuran/p/7568701.html