标签：nta any represent des i+1 一个 result 含义 表示
Given a non-negative integer represented as a non-empty array of digits, plus one to the integer.
You may assume the integer do not contain any leading zero, except the number 0 itself.
The digits are stored such that the most significant digit is at the head of the list.
题目含义：给定一个数组表示非负整数，其高位在数组的前面，对这个整数加1。
1 public int[] plusOne(int[] digits) { 2 int carry =1; 3 for (int i=digits.length-1;i>=0;i--) 4 { 5 int sum = carry + digits[i]; 6 digits[i] = sum%10; 7 carry = sum/10; 8 } 9 if (carry ==0) return digits; 10 int[] result = new int[digits.length+1]; 11 result[0] = carry; 12 for (int i=0;i<digits.length;i++) 13 { 14 result[i+1] = digits[i]; 15 } 16 return result; 17 }
标签：nta any represent des i+1 一个 result 含义 表示
原文地址：http://www.cnblogs.com/wzj4858/p/7701195.html
